A virus rests on the bottom plate of oppositely charged parallelplates in the va

Question

A virus rests on the bottom plate of oppositely charged parallelplates in the vacuum chamber of an electron microscope. Theelectric field strength between the plates is 2.00 x 10 to thepower of 5 N/C, and the bottom plate is negative. If the virus hasa mass of 1.00 x 10 to the power of -15 kg and suddenly acquires acharge of -1.60 x 10 to the power of -19 C, what are its velocityand position 75.0 ms later? do not disregard gravity?

answer is: y=6.24 cm.

Please give me a step by step solution. Thanks in advance.

Explanation / Answer

Electric field E = 2 * 10 ^ 5 N / C mass m = 1 * 10 ^ -15 kg charge q = -1.6 * 10 ^ -19 C time t = 75 ms = 0.075 s force due to electric field   = E q force due to gravity = m g So, net force F = E q - m g Accleration a = F / m from this we find a   value from the relation S = ut + ( 1/ 2 ) at^ 2 we find position S value . where  u = 0 m / s                       from the relation v = u + at from this we find velocity v value substitue values we get answer

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