The Velocity of the Electron has to be calculated in thedirection of the magneti

Question

The Velocity of the Electron has to be calculated in thedirection of the magnetic field. Since it makes an angle of 10degrees with the magnetic field, the velocity of the electron inthe direction of the magnetic field is vm= vcos() = (1.5e7m/s)cos(10)=1.48e7 m/s While it doesn't make that much of a difference for thisproblem (cos of 10 degrees is almost equal to 1), if the angle ischanged it can affect your calculations quite significantly. The Velocity of the Electron has to be calculated in thedirection of the magnetic field. Since it makes an angle of 10degrees with the magnetic field, the velocity of the electron inthe direction of the magnetic field is vm= vcos() = (1.5e7m/s)cos(10)=1.48e7 m/s While it doesn't make that much of a difference for thisproblem (cos of 10 degrees is almost equal to 1), if the angle ischanged it can affect your calculations quite significantly. While it doesn't make that much of a difference for thisproblem (cos of 10 degrees is almost equal to 1), if the angle ischanged it can affect your calculations quite significantly.

Explanation / Answer

Here         Distance d = vm T    = vm / f         vm = v cos              = 1.5 x 107 * cos 10             = 1.48 x 107 m /s Hence          d    =   ( 1.48 x 107 )* 2 me / e B             = ( 1.48 x 107 * 2 *9.11 x 10-31) / (1.602 x 10-19 * 1.0 x 10-3 T)             = 0.53 m Hope this helps u!

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