Two parrallel plates are 0.005m apart and are each 2m2in area.The plates are in

Question

Two parrallel plates are 0.005m apart and are each 2m2in area.The plates are in vacuum and an electric potentialdifference of 10,000V is applied across them. A) Find the capacitance, the charge on each plate, theelectric field intensity in the space between, and the storedenergy. B) If a dielectric material with dielectric constant K=80.4 isinserted into the gap between the plates, with the electricpotential remaining the same, find the new capacitance, charge oneach plate, electric field intensity, and energy stored. Two parrallel plates are 0.005m apart and are each 2m2in area.The plates are in vacuum and an electric potentialdifference of 10,000V is applied across them. A) Find the capacitance, the charge on each plate, theelectric field intensity in the space between, and the storedenergy. B) If a dielectric material with dielectric constant K=80.4 isinserted into the gap between the plates, with the electricpotential remaining the same, find the new capacitance, charge oneach plate, electric field intensity, and energy stored.

Explanation / Answer

Separation of the plates d = 0.005 m Area A = 2 m 2 electric potential difference V = 10,000V (A) . Capacitance C = o A / d where o = permitivity of free space =8.85 * 10 -12 C 2 / N m 2 Charge on each plate q = C V the electric field intensity in the space between thewplates E = q / A o the stored energy = ( 1/ 2) C V 2 ( B ) . dielectric constant K=80.4 New capacitance C ' = K C Charge on each plate q ' = C ' V electric field intensity E ' = q ' / A o energy stored = ( 1/ 2) C ' V 2 substitue values weget answer substitue values weget answer

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