T N b)Under the conditions of maximum traction, what is thetension in each cable

Question

                     T            N b)Under the conditions of maximum traction, what is thetension in each cable attached to the neck collar?                      T            N In treating spinal injuries, it is often necessary to providesome tension along the spinal column to stretch the backbone. Onedevice for doing this is the Stryker frame, illustrated in part (a)of the figure. A weight W is attached to the patient (sometimes around a neck collar, asshown in part (b) of the figure), and friction between the person'sbody and the bed prevents sliding. (Intro 1figure) a)If the coefficient of static friction between a80.5 kg patient^'s body and the bed is 0.780, what is the maximumtraction force along the spinal column that W can provide without causing the patient to slide? T N b)Under the conditions of maximum traction, what is thetension in each cable attached to the neck collar? T N

Explanation / Answer

     f is theforce, s is coefficient ofstatic friction, Fn is thenormal force fmax =(0.780)(80.5 kg(9.8 m/s2))

fmax =615.342 N

   If f is greater than fmax than slidingoccurs.
b) Sounder maximum traction the force is fmax which we found in part a. Fmax = 615.342 N
Alright,so I'll be looking at only one cable since the other cable is the"same". So force is 615.342 N divided by 2.
(1/2)(615.342 N) = sin(65)(x)
Where xis the tension on one of the cables.

x =339.477 N

If youdon't understand why I did what I did, just ask.

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