QuestionDetails: As part a of the drawing shows, two blocks areconnected by a ro

Question

QuestionDetails: As part a of the drawing shows, two blocks areconnected by a rope that passes over a set of pulleys. One blockhas a weight of m1 = 412 N, and the other has a weight ofm2 = 958 N. Therope and the pulleys are massless and there is no friction. What do I need to do to find the acceleration of the lighterblock? What if someone applies (pulls the rope) the same amount ofdownward force for the same pulley instead of the heavier blockpulling on the rope? QuestionDetails: As part a of the drawing shows, two blocks areconnected by a rope that passes over a set of pulleys. One blockhas a weight of m1 = 412 N, and the other has a weight ofm2 = 958 N. Therope and the pulleys are massless and there is no friction. What do I need to do to find the acceleration of the lighterblock? What if someone applies (pulls the rope) the same amount ofdownward force for the same pulley instead of the heavier blockpulling on the rope?

Explanation / Answer

To solve for this use the equation m2g-T=m2a and T-m1g=m1a.This becomes a=((m2-m1)/(m2+m1))g . Now solve for theacceleration. The same thing happens for the second question,but this time it's a person and not a block.

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