A ski jumper starts from rest 44.0 m above the ground on a frictionlesstrack and

Question

A ski jumper starts from rest 44.0 m above the ground on a frictionlesstrack and flies off the track at an angle of 45.0° above thehorizontal and at a height of 14.0 m above the ground. Neglect airresistance. (a) What is her speed when she leaves the track?
m/s

(b) What is the maximum altitude she attains after leaving thetrack?
m

(c) Where does she land relative to the end of the track?
m
(a) What is her speed when she leaves the track?
m/s

(b) What is the maximum altitude she attains after leaving thetrack?
m

(c) Where does she land relative to the end of the track?
m

Explanation / Answer

a) Velocity of theperson before he left th e track
mv2 / 2 = mgh - mgh'
h = 44m h' = 14 m = mss of the person v = velocity of the person
From the above relation we can solve for the velocity of the person' v '
b) The maximum h reightreached by the person
h = v sin2 / 2g = 45 g = 9.8 m/sec2 v = velocity of the person        c) Horizantaldistance ' S ' travelled during the journey
S = vcos * t t = time of flight
Time of flight vcan be solve from
h = v sin t - gt2 / 2 h = maximum height reached = angle of projection g = accleration due to gravity .

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