this is part two of a ? I found the velocity vector(part 1)which was v=12t^3i -

Question

this is part two of a ? I found the velocity vector(part 1)which was v=12t^3i - (8t+3)j. Part two asks: Find the magnitude of the above velocity at t= 2 sec. This is a multiple choice problem and my answer was 94.1. this is four numbers off from the lowest answer which is 98. I needa step by step so I can see what I have done wrong. I plugged inthe 2, squared the answers, added them together, and found thesquare root.   Pleasehelp.         thisproblem is from a study guide. this is part two of a ? I found the velocity vector(part 1)which was v=12t^3i - (8t+3)j. Part two asks: Find the magnitude of the above velocity at t= 2 sec. This is a multiple choice problem and my answer was 94.1. this is four numbers off from the lowest answer which is 98. I needa step by step so I can see what I have done wrong. I plugged inthe 2, squared the answers, added them together, and found thesquare root.   Pleasehelp.         thisproblem is from a study guide.

Explanation / Answer

You are doing everything correctly. When I inserted t=2into your equation, I got 97.86 which rounds to 98. I believe you just have a simple arithmetic error. Donot subtract the velocity in j^ direction because you are squaringit to make it positive. For e.g. Velocity Component notation: v = (96)^2 +(-19)^2 = 9577 and not... 8855

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