A quarterback throws a football straight toward a receiverwith an inital speed o

Question

A quarterback throws a football straight toward a receiverwith an inital speed of 20.0 m/s, at an angle of 30 degrees abovethe horizontal. At that instant, the receiver is 20m from thequarterback. In what direction and with what constant speed shouldthe receiver run to catch the football at the level at which it wasthrown? I know the velocity is 7.5 m/s, just not sure how you get it,and no idea for direction Please show work A quarterback throws a football straight toward a receiverwith an inital speed of 20.0 m/s, at an angle of 30 degrees abovethe horizontal. At that instant, the receiver is 20m from thequarterback. In what direction and with what constant speed shouldthe receiver run to catch the football at the level at which it wasthrown? I know the velocity is 7.5 m/s, just not sure how you get it,and no idea for direction Please show work

Explanation / Answer

First thing you need to do is determine how long the ball willbe in the air Use this equation: df=di + vit +(1/2)gt2 vi is the initial verticle speed which would be20sin300.The df and di are theintial and final height which will both be zero. g is -9.8 m/s2 and you solve for t 0=0+ (t)20sin(30) + (1/2)(-9.8)t2 . . you should get 2.04sec. . Now plug that time into the simple speed equation: d=vt d is distance. t is the time that you just found and v is thehorizontal speed 20cos300. d=(20cos30)(2.04) =35.33 meters . . The reciever is at d=20 meters so he has to move35.33-20=15.33 metersin the time it takes for the ball to reach it's final height. d=vt v=d/t =15.33/2.04 =7.51 m/s away from theQB

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