a parallel- plate capcitor has a plate area of 0.4 meterssquared and a separatio

Question

a parallel- plate capcitor has a plate area of 0.4 meterssquared and a separation of 0.1 mm. How much charge accumulates onits plates when it connected to a 12V? How much energy is stored inits feild? i came up with 3.54x10^-8 for how much charge the plate willaccumulate and 2.549x10^-6 for total storage. i didnt get fullcredit for the problem but i need a little help in where i wentwrong. a parallel- plate capcitor has a plate area of 0.4 meterssquared and a separation of 0.1 mm. How much charge accumulates onits plates when it connected to a 12V? How much energy is stored inits feild? i came up with 3.54x10^-8 for how much charge the plate willaccumulate and 2.549x10^-6 for total storage. i didnt get fullcredit for the problem but i need a little help in where i wentwrong.

Explanation / Answer

   Capacitance   C   =   0* A / d   =   8.85 * 10-12* 0.4 / 0.1 *10-3   =   3.54 *10-8   F    Charge   Q   =   C* V   =   3.54 * 10-8 *12   =   4.25 *10-7   C    Energystored   U   =   (1/2)* Q * V   =   0.5 * 4.25 *10-7 * 12       U   =   2.55* 10-6   J

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