point 2 m/s point 3 m/s point 4 m/s Solution Okay I haven\'t been able to upload

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Okay I haven't been able to upload a picture so I'll just try toexplain the best way I can. Lets begin: First lets find what the velocity will be at point 2:                       Ei=Ef If we say that at point 2, the potential Energy is zero. ------->mgh1=1/2mv2 we can cancel out the mass and multiply both sides by 2 and takethe square root of both sides and you got your speed for point2. 2gh1=v=24.2487 we could go from point 2 to point 3 to find the velocity at point3, but the beauty of energy is that it is always conserved, thatmeans that we can go from from point 1 to point 3 right?                    Ei=Ef --------->mgh1=mgh3 +1/2mv23 again we can cancel out the m subtract gh3 from bothsides, multiply both sides by 2 and take the square root and findthe v for    point 3 [2g(h1-h3)=v= 6.26099033 now the last one, in this one we can do the same as for point 3,just go from the begining and to the end points and account for theEnegy. ----->>>mgh1=mgh2+(1/2)mv24 cancel out the masses, and subtract gh2 from both sidesmultiply by 2 both sides and take the square root from both sidesand get the velocity at point 3 2g(h1-h2)=v=20.287927 Hope that helps.

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