I am stuck on the following problem. It looks simple, but Idon\'t know where to

Question

I am stuck on the following problem. It looks simple, but Idon't know where to begin:
A grasshopper jumps 1.50 m from rest, with an initial velocityat 46.0 degree angle with respect to the horizontal. a) Find the initial speed of the grasshopper (in m/s)
b) Find the maximum height reached (in m).
Thank you!
A grasshopper jumps 1.50 m from rest, with an initial velocityat 46.0 degree angle with respect to the horizontal. a) Find the initial speed of the grasshopper (in m/s)
b) Find the maximum height reached (in m).
Thank you!

Explanation / Answer

Given that The distance the grasshopper landed is (R) =1.50m The angle with the horizontal () =460 Accelration due to gravity(g) =9.8m/s2 Accelration due to gravity(g) =9.8m/s2 a) We know that            R = u2sin2/g The initial speed of the grasshopper is (u) =Rg/sin2 Now substitutte all the above values you get the requiredanswer b) The maximum height reached is given by                   Hmax =u2sin2/2g Substitute the value of part (a) to the height

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