An eagle is flying horizontally at 5.4 m/swith a fish in its claws. It accidenta

Question

An eagle is flying horizontally at 5.4 m/swith a fish in its claws. It accidentally drops the fish. (a) How much time passes before the fish'sspeed quadruples?
1 s

(b) How much additional time would be required for the fish's speedto quadruple again?
2 s

Section 3.2 Equations of Kinematics in twoDimensions
Section 3.3 ProjectileVelocity
(a) How much time passes before the fish'sspeed quadruples?
1 s

(b) How much additional time would be required for the fish's speedto quadruple again?
2 s
Section 3.2 Equations of Kinematics in twoDimensions
Section 3.3 ProjectileVelocity

Explanation / Answer

the vertical speed would change like at(acceleration x time) =9.81t
horizontal speed remains constant so 5.4 and it is the initialspeed

overall speed is (x^2+y^2)^(1/2)= (5.4^2 + 9.81^2 t^2)^1/2

(a) How much time passes before the fish's speed quadruples?

final speed=4 x initial = 29.16
so
29.16=(5.4^2 + 9.81^2 t^2)^1/2
850.3056=29.16+96.2361t^2
t^2=8.53.26 >> t=2.92s


(b) How much additional time would be required for the fish's speedto quadruple again?
same reasoning

final speed=4(4x(initial))=86.4
86.4=(5.4^2 + 9.81^2 t^2)^1/2
7464.96=29.16+96.2361t^2
t=8.79

additional time=overall time-original time=8.79-2.92=5.87

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