A 4.2-g lead bullet moving at 275 m/s strikes a steel plateand stops. If all its

Question

A 4.2-g lead bullet moving at 275 m/s strikes a steel plateand stops. If all its kinetic energy is converted to thermal energyand none leave the bullet, what is the temperature change? * What equation is used in this exactly?? Please helpand I will be sure to rate highly. A 4.2-g lead bullet moving at 275 m/s strikes a steel plateand stops. If all its kinetic energy is converted to thermal energyand none leave the bullet, what is the temperature change? * What equation is used in this exactly?? Please helpand I will be sure to rate highly.

Explanation / Answer

Mass of bullet M = 4.2 g = 4.2 * 10 -3kg Change in kinetic energy K = ( 1/ 2) M v2 where  v = speed = 275 m / s So, K = 158.8125 J This energy is used to increse the temp . So, heat taken   m C dt = 198375 J from this Increse in temperature dt = 158.8125 J /( m C ) where C = Specific heat of steel = 500 J / kgo C So, dt = 0.3176 o C Change in kinetic energy K = ( 1/ 2) M v2 where  v = speed = 275 m / s So, K = 158.8125 J This energy is used to increse the temp . So, heat taken   m C dt = 198375 J from this Increse in temperature dt = 158.8125 J /( m C ) where C = Specific heat of steel = 500 J / kgo C So, dt = 0.3176 o C

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