I am confused by the solution to the problem: Henrietta runsfrom the apartment d
ID: 1736289 • Letter: I
Question
I am confused by the solution to the problem: Henrietta runsfrom the apartment door 3.05m/s. 9 seconds after she leaves hubbythrows her lunch out of the window 43.9m above ground. shecatches it on the run. Ignoring air resistance, (a) with whatinitial speed must Hubby throw the lunch so that Henrietta cancatch it just before it hits the ground, (b) where is Henriettawhen she catches the bagels? The solution provided seems incomplete t= 2x43.9/9.8 ? Why square double the height divided bygravity? The 9 seconds is then neglected? *("See how to write a valid question" is down and I've neverused this before) I am confused by the solution to the problem: Henrietta runsfrom the apartment door 3.05m/s. 9 seconds after she leaves hubbythrows her lunch out of the window 43.9m above ground. shecatches it on the run. Ignoring air resistance, (a) with whatinitial speed must Hubby throw the lunch so that Henrietta cancatch it just before it hits the ground, (b) where is Henriettawhen she catches the bagels? The solution provided seems incomplete t= 2x43.9/9.8 ? Why square double the height divided bygravity? The 9 seconds is then neglected? *("See how to write a valid question" is down and I've neverused this before)Explanation / Answer
the square root gives you time
the 2 is because of equations like x-xo = 1/2 at^2
the time you get from this would be added to the 9 seconds tofind the total time henrietta has been gone
let me know if you need anything else
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.