PartA - Find the total charge stored in thisnetwork. PartB - Find the charge on

Question

PartA - Find the total charge stored in thisnetwork.
PartB - Find the charge on each capacitor.
PartC - Find the total energy stored in thenetwork.
PartD - Find the energy stored in eachcapacitor.
PartE - Find the potential difference across eachcapacitor. PartA - Find the total charge stored in thisnetwork.
PartB - Find the charge on each capacitor.
PartC - Find the total energy stored in thenetwork.
PartD - Find the energy stored in eachcapacitor.
PartE - Find the potential difference across eachcapacitor. PartA - Find the total charge stored in thisnetwork. PartB - Find the charge on each capacitor. PartC - Find the total energy stored in thenetwork. PartD - Find the energy stored in eachcapacitor. PartE - Find the potential difference across eachcapacitor.

Explanation / Answer

A. total capacitance C=35nF+75nF=110nF total chargeQ=CV=110nF*220V=110*10-9F*220V=2.42*10-5C B. Q35nF = 35nF*220V=7.7*10-6 C Q75nF=75nF*220V=1.65*10-5C C. Wstored =(1/2)CV2=0.5*110*10-9F*(220V)2=2.662*10-3J D. W35nF =(1/2)CV2=0.5*35*10-9F*(220V)2=8.47*10-4J W75nF =(1/2)CV2=0.5*75*10-9F*(220V)2=1.815*10-3J E. V35nF=V75nF = V = 220V

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