A cyclist, traveling at a constant velocity begins toaccelerate at a rate of .45

Question

A cyclist, traveling at a constant velocity begins toaccelerate at a rate of .45m/s2. After 8 secondsof acceleration the cyclist's velocity is 10.9 m/s. What wasthe initial velocity. The answer is 7.3 m/s. I need to understand what formulas are applied here and how towork the problem. Thanks A cyclist, traveling at a constant velocity begins toaccelerate at a rate of .45m/s2. After 8 secondsof acceleration the cyclist's velocity is 10.9 m/s. What wasthe initial velocity. The answer is 7.3 m/s. I need to understand what formulas are applied here and how towork the problem. Thanks

Explanation / Answer

Velocity after 8 s is v = 10.9 m / s Accleration a = 0.45 m / s ^ 2 from the relation v = u + at initial velocity u = v - at                        = 10.9 - 3.6                        = 7.3 m / s

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