A 75kg man steps off a platform 3.10m above the ground .Hekeeps his legs straigh

Question

A 75kg man steps off a platform 3.10m above the ground .Hekeeps his legs straight as he falls but at the moment his feettouch the ground his kee began to bend ,and ,treated as particle hemoves an additional 0.62m before coming to rest a) what is his speed at the instant his feet touch the ground? b)treating him as particle what is his acceleration (magnitudeand direction) as he slows down if the acceleration assumedto be constant c)draw his free body diagram in terms of forces on diagramwhat is net force on him ? use newton laws and the result of part bto calculte the average forces his feet exert on the ground whilehe slows down express these forces in newton and also as a multipleof his weight A 75kg man steps off a platform 3.10m above the ground .Hekeeps his legs straight as he falls but at the moment his feettouch the ground his kee began to bend ,and ,treated as particle hemoves an additional 0.62m before coming to rest a) what is his speed at the instant his feet touch the ground? b)treating him as particle what is his acceleration (magnitudeand direction) as he slows down if the acceleration assumedto be constant c)draw his free body diagram in terms of forces on diagramwhat is net force on him ? use newton laws and the result of part bto calculte the average forces his feet exert on the ground whilehe slows down express these forces in newton and also as a multipleof his weight

Explanation / Answer

a. The distance at which he touches the ground is d=3.1-0.62=2.48m v2-u2=2gh v2-0=2*g*2.48 v=6.97m/s b. v2-u2=2as 0-6.972=2*a*0.62 a=39.2m/s2 c. The net force on him is F=ma F=75*39.2 F=2940N c. The net force on him is F=ma F=75*39.2 F=2940N

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