A mountain climber stands at the top of a 25.0 m cliff that overhangs a calm poo

Question

A mountain climber stands at the top of a 25.0 m cliff that overhangs a calm pool of water. Shethrows two stones vertically downward 1.00 s apart and observesthat they cause a single splash. The first stone had an initialvelocity of -1.00m/s. (a) How long after release of the first stonedid the two stones hit the water?
(b) What initial velocity must the second stone have had, giventhat they hit the water simultaneously?
(c) What was the velocity of each stone at the instant it hit thewater? first stone _____ ? second stone _____? (a) How long after release of the first stonedid the two stones hit the water?
(b) What initial velocity must the second stone have had, giventhat they hit the water simultaneously?
(c) What was the velocity of each stone at the instant it hit thewater? first stone _____ ? second stone _____?

Explanation / Answer

(a) How long after release of the first stone did the two stoneshit the water?        v ' = - [vo2 + 2 a h]    = - [-1.402 + 2 * 9.8 * 35 ]            = -26.14 m/s Therefore        t = v' - vo / a          = - 26.14 +1.40 / -9.8          = 2.525 s (b) What initial velocity must the second stone have had, giventhat they hit the water simultaneously?          vo' = h - 0.5 at'2 / t'              = -35 +0.5 * 9.8 * 1.0 / 1.0              = -30.1 m/s (c) What was the velocity of each stone at the instant it hit thewater?      final velocity of first stone v' = -26.14m/s      for second stone                v'' = vo ' + at'                    =-30.1 - 9.80 * 1                    = -39.9 m/s

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