A parallel-plate capacitor has capacitance 6.00 µF. (a) How much energy is store

Question

A parallel-plate capacitor has capacitance 6.00 µF. (a) How much energy is stored in the capacitorif it is connected to a 24.00 Vbattery?
1 µJ

(b) If the battery is disconnected and the distance between thecharged plates doubled, what is the energy stored?
2 µJ

(c) The battery is subsequently reattached to the capacitor, butthe plate separation remains as in part (b). How much energy isstored?
3 µJ (a) How much energy is stored in the capacitorif it is connected to a 24.00 Vbattery?
1 µJ

(b) If the battery is disconnected and the distance between thecharged plates doubled, what is the energy stored?
2 µJ

(c) The battery is subsequently reattached to the capacitor, butthe plate separation remains as in part (b). How much energy isstored?
3 µJ

Explanation / Answer

(a) energy stored = (1/2)CV2 = (1/2) * 6.00 * 24.02=   1728 J . (b) the energy doubles to     3456 J . (c)   the capacitance is only half as much when theplates are doubled, so the new energy stored is .        (1/2) * 3.0 *24.02=    864J

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