A) Three charges, Q 1 , Q 2 , and Q 3 are located in a straight line. The positi

Question

A)
Three charges, Q1, Q2, andQ3 are located in a straight line. The positionof Q2 is 0.279 m to the right ofQ1. Q3 is located 0.158 mto the right of Q2. The force onQ2 due to its interaction withQ3 is directed to the (Give ALL correctanswers, i.e., B, AC, BCD...)

A) left if the two charges are negative.
B) left if the two charges have opposite signs.
C) right if the two charges are negative.
D) left if the two charges are positive.
E) right if the two charges have opposite signs.

B)

In the above problem, Q1= 1.39x10-6C, Q2=-3.22 x10-6C, and Q3= 3.33 x10-6C. Calculate the total force on Q2.Give with the plus sign for a force directed to the right?

plz help

Explanation / Answer

options C and E are right assuming that Q2 is positive. the force on Q2 due to Q1 F1=9*109*1.39x10-6*3.22x10-6/0.279*0.279=517.49*10-3 N
similarly the force on Q2 due to Q1 F2=9*109*3.33x10-6*3.22x10-6/0.158*0.158=3865.70*10-3 N net force =F2-F1=3865.70*10-3N-517.49*10-3 N =3348.21*10-3N net force =F2-F1=3865.70*10-3N-517.49*10-3 N =3348.21*10-3N

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