An uncharged solidconducting sphere of radius r0 contains twospherical cavities,

Question

An uncharged solidconducting sphere of radius r0 contains twospherical cavities, one with the radius r1 and another– with the radius r2.Positive point charge Q1 is placedwithin the first cavity, and positive point chargeQ2 is placedwithin the second cavity. What is the resulting electric field(magnitude and direction) at locations outside the sphere(r>r0 where ris the distance from the center of thesphere)? nonumeric solution expected.

Explanation / Answer

An unchargedsolid conducting sphere of radius r0 containstwo spherical cavities, one with the radius r1 and another– with the radius r2.Positive point chargeQ1 is placed within the first cavity, and positive pointcharge Q2is placed within the secondcavity. What is the resulting electric field (magnitude anddirection) at locations outside the sphere (r>r0 where r is the distance from the center of the sphere)? Non-numeric solution expected. Applying Gauss's Law to sphericalsurface (of radius "r") which is outside of and concentric to conducting sphere, we obtain:      (4*Pi*(r)^2)*E = (Q_enclosed)/0      ---->   (4*Pi*(r)^2)*E = ((Q_1) +(Q_2))/0      ---->    E = ((Q_1) + (Q_2))/(0*4*Pi*(r)^2) {E Field Magnitude} = ((Q1) + (Q2))/(4*Pi*0*(r)^2) {E Field Direction} = {Radially Outward} .

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