If an object 18 millimeters high is placed 12 millimeters froma diverging lens a

Question

If an object 18 millimeters high is placed 12 millimeters froma diverging lens and the image is formed 4 millimeters in front ofthe lens, wnat is the height if the image? (a) 6millimeters                        (c) 14 millimeters (b) 8millimeters                         (d) 22 millimeters If an object 18 millimeters high is placed 12 millimeters froma diverging lens and the image is formed 4 millimeters in front ofthe lens, wnat is the height if the image? (a) 6millimeters                        (c) 14 millimeters (b) 8millimeters                         (d) 22 millimeters

Explanation / Answer

The height of the object placed in front of a diverginglens is O = 18 millimeters The distance of the object from the diverging lens is u = 12millimeters The image formed by the lens is 4 millimeters in front of thelens We know from the relation (v/u) = (I/O) Here,v = 4 millimeters and I is the height of theimage. or I = (v/u) * O or I = (4/12) * 18 = 6 millimeters Therefore,the height of the image is I = 6 millimeters.

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