1) A molecule of DNA (deoxyribonucleic acid) is 2.15 µm long. The ends of the mo
ID: 1733828 • Letter: 1
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1) A molecule of DNA (deoxyribonucleic acid) is 2.15 µm long. The ends of the molecule becomesingly ionized -- negative on one end, positive on the other. Thehelical molecule acts as a spring and compresses 0.88% upon becoming charged. Determine the effectivespring constant of the molecule. Can someone please write the stepsout for me? I need to compare my work to it. 1) A molecule of DNA (deoxyribonucleic acid) is 2.15 µm long. The ends of the molecule becomesingly ionized -- negative on one end, positive on the other. Thehelical molecule acts as a spring and compresses 0.88% upon becoming charged. Determine the effectivespring constant of the molecule. Can someone please write the stepsout for me? I need to compare my work to it.Explanation / Answer
This question cannot be solved as you have presented it herefor one reason, you do not have enough information, and hereswhy Force (spring) = Fs =-kx where k is the spring constant in N/m, and x is the compression(meters) we know the molecule acts like a spring and compresses 0.88%(2.15x10-6m) x 0.0088 = 18.92x10-9 m Now we have F=1.892x10-8 k We need to know the force to solve for k, the spring constant (itcan also be solved if you know the energy, the formula is E=1/2 kx2) REPLY TO COMMENT: Even with the F=k q1 q2 / r2, you still need to know q1and q2 to calculate F Nowhere in your problem did you include those All I said is that the question cannot be solved with theinformation you have presented, which is still true now
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