An iron anchor of density 7870 kg / m^3 appears 200 N lighterin water than in ai

Question

An iron anchor of density 7870 kg / m^3 appears 200 N lighterin water than in air. (a) What is the volume of theanchor? (b) How much does it weigh in air? The answers given were a) 2.97*10^-3 m^3 and b) Force ofgravity = 229.03 N CAN SOMEONE HELP ME? I set up the equations separately for when the anchor is inthe air and when it is in water, but I am getting stuck afterthat An iron anchor of density 7870 kg / m^3 appears 200 N lighterin water than in air. (a) What is the volume of theanchor? (b) How much does it weigh in air? The answers given were a) 2.97*10^-3 m^3 and b) Force ofgravity = 229.03 N CAN SOMEONE HELP ME? I set up the equations separately for when the anchor is inthe air and when it is in water, but I am getting stuck afterthat

Explanation / Answer

The answers given to you are incorrect. The correct answersare highlighed below. The idea is that the buoyancy force is equal to the differencein the apparent and actual weight of the anchor. So...     buoyancy force = 200N This is also equal to the weight of the water displaced.So...     weight of water displaced =   volume of water * density of water * g             200       =      V * 1000 * 9.8        V =   0.0204 m3       This is also the volume of the anchor, because it displaces anequal volume of water. How much does it weight in air? That is, what is itsactual weight?     actual mass = density *volume =   7870 * 0.0204   = 160.6 kg    actual weight = mg = 160.6 * 9.8   =    1574 N

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