You push a 325N trunk up20.0 degrees inclined plane at a constant velocity by se

Question

You push a 325N trunk up20.0 degrees inclined plane at a constant velocity by settingg a211N forceParallell to theplane'ss surface.
A.) what is the component o th trunks weight parallel to theplane?
B.) what is the sum of all forces parallel to the plane'ssurface?
C.) what are the magnitude and direction of the friction force?
D.) What is the coefficient of friction? A diagram would be great. You push a 325N trunk up20.0 degrees inclined plane at a constant velocity by settingg a211N forceParallell to theplane'ss surface.
A.) what is the component o th trunks weight parallel to theplane?
B.) what is the sum of all forces parallel to the plane'ssurface?
C.) what are the magnitude and direction of the friction force?
D.) What is the coefficient of friction? A diagram would be great. A diagram would be great.

Explanation / Answer

A. W=325sin20=111.16N B. F=211-111.16=99.84N C. The frictional force fr=F=99.84N This is in downward direction of the motion of the block ofit. D. Frictional force is fr=N fr=mg =fr/mg =99.84/325 =0.30721 Hence we get by it. "Hope this helps!Best of luck for the rest of yourcoursework."

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