Part A Consider the circuit shown in the following figure (Figure 1), but with t

Question

Part A Consider the circuit shown in the following figure (Figure 1), but with the bar moving to the right with speed v. The bar has length 0.372 m, R- 45.62, and B-0.664 T Is the induced current in the circuit clockwise or counterclockwise? clockwise counterclockwise Submit uest Answer Part B Figure 1 of 1 At an instant when the resistor is dissipating electrical energy at a rate of 0.829 J/s, what is the speed of the bar? Express your answer with the appropriate units. Yalue Units Submit uest Answer

Explanation / Answer

A)

since bar moves to left, flux is increasing

So, induced magnetic field should be opposite to actual magnetic field.

So, induced magnetic field will be downward.

Curling fingers of right hand pointing thumb in direction of magnetic field gives the direction of current

Current will be clockwise

Answer: clockwise

B)

Power,

P = 0.829 J/s

use:

P = E^2/R

0.829 = E^2 / 45.6

E^2 = 37.8024

E = 6.15 V

This is induced emf

Now use:

induced emf,

E = B*L*V

6.15 = 0.664 * 0.372 * V

V = 24.9 m/s

Answer: 24.9 m/s

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