Prince Al Hussein Bin Abdulah I1 Academy of Civil Protection General Physics.: (

Question

Prince Al Hussein Bin Abdulah I1 Academy of Civil Protection General Physics.: (30201102) Instructor: Dr. Emad Alhami Time: 1300 1400 Student's NameAl _._Seld-shee? Student's Name: 2015 20 29 Q1: The electric field lines for a positive point charge are: a) uniform b) directed toward the charge b) non-uniform d) cross each other 02: Tow point charges (qi -1C:q-3 JC 1,their coordinates are (0,0) and (0,30cm) respectively. The position at which the electric net force equals to zero is: a) (0,15) b) (15,0) c) (7.5,0) d) (0,7.5) Q3: An electron is projected out along the ex axis with initial speed of 3*10°m/s. It goes 45cm and stops due to a uniform electric field in the region. The magnitude of the field ( in V/m) is a) 114 b) 57 c) 28.5 d) 14.25 Q4:In previous question, the direction of the field will be in the direction of: a) ty direction b) -y direction c)+x direction d)-x direction Q5: An electric field of 3KN/C is applied along the y axis. The electric flux through a circular plane of radius 0.4 m2 that lies in the xz plane ( inV.m) is: a) 0 b)4524 c)3016 d) 1507

Explanation / Answer

Solution:

1) electric field due to positive point charge is uniform

2) k * q * 1 / x^2 = k * q * 3^2 / (0.3 - x)^2

=> 1 / x^2 = 9 / (0.3 - x)^2

=> 0.09 + x^2 - 0.6 x = 9 x^2

=> 8x^2 + 0.6 x - 0.09 = 0

x = 0.075  

option c should be right ( 7.5 , 0)

3) Using 0.5 * m v^2 = e * V

=> 0.5 * 9.1 * 10^-31 * 9 * 10^12 = 1.6 * 10^-19 * V

=> V = 25.59 V

E = 25.59 / 0.45

=> E = 57 V/m (option b)

4) + x direction

5) flux = 3 * 10^3 * 3.14 * 0.4 * 0.4

=> flux = 1507 Nm^2 / C

please rate thanks.

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