17. +1/6 points | Previous Answers SerCP9 19.P048 The two wires shown in the fig

Question

17. +1/6 points | Previous Answers SerCP9 19.P048 The two wires shown in the figure below are separated by d = 12.1 cm and carry currents of I = 5.30 A in opposite directions 2d (a) Find the magnitude and direction of the net magnetic field at a point midway between the wires. magnitude direction 1.76 5 Your response differs from the correct answer by more than 10%. Double check your calculations. ?? into the page (b) Find the magnitude and direction of the net magnetic field at point Pi, 12.1 cm to the right of the wire on the right. magnitude directiorn 24.2 cm to the left of the wire on the left. (c) Find the magnitude and direction of the net magnetic field at point P2, 2d magnitude direction Need Help?Talk to a Tutor

Explanation / Answer

a)

Bnet = -µ0I/[2?(d/2)] - µ0I/[2?(d/2)] = -µ0I/2?d

Plugging values,

Bnet = -(4?*10^-7*5.30)/(2?*0.121) = -8.76*10^-6 T =8.76µT

By right hand rule directed into the page

b)

Bnet = µ0I/[2?d] - µ0I/[2?(2d)] = µ0I/[2?d] - µ0I/[4?d)] = µ0I/[4?d)]

Plugging values,

Bnet = (4?*10^-7*5.30)/(4?*0.121) = 4.38*10^-6 T = 4.38µT

By right hand rule directed out of the page

c)

Bnet = µ0I/[2?*(2d)] - µ0I/[2?(3d)] = µ0I/[4?d] - µ0I/[6?d)] = µ0I/[12?d)]

Plugging values,

Bnet = (4?*10^-7*5.30)/(12?*0.121) = 1.46*10^-6 T =1.46µT

By right hand rule directed out of the page

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