(790) Problem 10: In the figure, the point charges are located at the corners of
ID: 1731288 • Letter: #
Question
(790) Problem 10: In the figure, the point charges are located at the corners of an equilateral triangle 25 ? on a side. la Ic Otheexpertta.com ? 25% Part (a) Find the magnitude of the electric field in NC at the location of qa, given that qb-8.hc and q.--5.6 pC Grade Summary Deductions 0% Potential 100% cos0 sinO cotanO asin acos atan acotan0 sinh0 osh tanhO cotanh0 Submissions Attempts remaining: 3 % per attempt) detailed view Degrees Radians SubitHet I give up! ? Hint Feedback:-% deduction per feedback. = ? 25% Part (b) Find the direction of the electric field at qa in degrees above the negative x-axis with ongin at 9a 25% Part (c) What is the magnitude of the free in N on qa, given that qa-1,1 nC? 25% Part (d) What is the direction of the force on qa in degrees above the negative x-axis with origin at 92Explanation / Answer
a )
for qb
E = k q/ r2
= 9 X 109 X 8.1 X 10-6 / 0.252
E = 1166400 N/C
x ---> 166400 X cos60 = 583200 N/C left
y ---> 806400 X sin60 = 1010132 N/C up
for qc
E = k q/ r2
= 9 X 109 X 5.6 X 10-6 / 0.252
E = 806400 N/C
x ---> 806400 X cos60 = 403200 N/C left
y ---> 806400 X sin60 = 698362.9 N/C up
x = 583200 + 403200
= 986400 N/C
y = 1010132 + 698362.9
= 1708494.9 N/C
E = ( 9864002 + 1708494.92 )1/2
E = 1972799.98 N/C
b )
angle = tan-1 ( 1708494.9 / 986400 )
angle = 60o
c )
F = q E
= 1.1 X 10-6 X 1972799.98
F = 2.17 N
d )
angle = tan-1 ( 1708494.9 / 986400 )
angle = 60o
above neagitve x axis.
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