Wave and Sounds #5 (2090) Problem 5: Consider the double pulley system in the fi

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Wave and Sounds #5

(2090) Problem 5: Consider the double pulley system in the figure, with two hanging two masses, where M1 52 kg and M2 2.5. The string has a mass density of?-55 g/m which is much smaller than either of the hanging masses, and there is no friction in the pulleys Otheexpertta.com 25% Part (a) Give an expression for the acceleration of the system, assuming the positive direction is towards the larger mass Grade-97% Correct Answer Student Final Submission Feedback ?-(M1-M2 )( MI-M2 ) g Grade Summary a-(-(M2 -Mi (M2+Mi))g Correct! Deduction for Final Submission Deductions for Incorrect Submissions, Hints and Feedback [?] Student Grade-100-0-3-97% 0% 3% Submission History All Date times are displayed in Pacific Standard Time. Red submission date times indicate late work Hints Date Jul 28, 2018 Jul 28, 2018 Answer Feedback l ime 6:33 PM 6:35 PM 1 a ((M2 - Mi)(M2 +Mi))g Note: Feedback not accessed. 2 25% Part (b) What would the speed of a wave on this string be, in meters per second, assuming the string is at rest? -? 25% Part (c) A student disturbs the string, setting up a wave which travels as shown in the figure. In the frame of the lab, what is the velocity (in meters per second, with the positive direction towards the heavy mass) of the wave on the string after t? 2.6 s? 25% Part (d) At what time (in s) would the wave appear to be momentarily motionless in the frame of the lame? All content 2013 Expert T, LLC

Explanation / Answer

b] Here a = (52-2.5)/(52+2.5)*9.8 = 8.9 m/s^2

tension T = M2*(g+a) = 2.5*(9.8+8.9) = 46.75 N

speed v1 = sqrt(T/rho) = sqrt(46.75/0.055) = 29.15 m/s

c] velocity v = at - v1 = 8.9*2.6 - 29.15 = -6.01 m/s

d] Here, v = at - v1 = 0

t = 29.15/8.9

= 3.275 s answer

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