Part A A thin, uniform, metal bar, 2.50 m long and weighing 90.0 N, is hanging v

Question

Part A A thin, uniform, metal bar, 2.50 m long and weighing 90.0 N, is hanging vertically from the ceiling by a frictionless pivot. Suddenly it is struck 1.40 m below the ceiling by a small 4.00-kg ball initially traveling horizontally at 14.0 m/s. The ball Find the angular speed of the bar just after the collision in the opposite direction with a speed of 7.00 m/s rad/s You may want to review (Pages 320-322) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Angular Submit Part B During the collision, why is the angular momentum conserved but not the linear momentum? Essay answers are limited to about 500 words (3800 characters maximum, including spaces). 3800 Characters) remaining Submit est Ans

Explanation / Answer

Considering conservation of angular momentum

m*v1*d = Ip*w -*mv2*d . (1)

Ip= M*l^2/3= (90/9.81)*2^2/3=12.245 kg-m2
Putting in (1)
12.245*w = 4*1.4*(14+7)
w = 9.6 rad/s

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As equal and opposite torque applied on the system hence angular momentum is conserved for same time interval.

the ball impact the system as an external force, hence linear momentum can't be considered to be constant.

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