EAssignments ? ? Oopenvellumacollege C-30c8b5771c343599f4c1ba28c328730ct 10301 1
ID: 1731082 • Letter: E
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EAssignments ? ? Oopenvellumacollege C-30c8b5771c343599f4c1ba28c328730ct 10301 14 MyLabsPlus Course Home Item 10 10 of 10 hattotal encray can be sucplird by a 13 V, A hbartery its intemal recistanc mepib? Fxpnass your answar using rwo aipnificant finurea. Scorcs Course Toos Chapler Content Text lectricalsystams, is rated in ampers-haurs (A h) A5 A hhatary can Ieer Salting- Part Exprass your answar using two sipnificant fiqures. ??? Part C r a ganerator wth an avarape dectrical par cutpul o0 35 kWis connectad to te baltery, haw much tme wil be requred 1r to charge the batary tuly 3:43 PM P * ENG 20183Explanation / Answer
Power of battery = V *I
Energy Total = P * time(in seconds )= V *I *3600=13*40*3600=1,872,000 J
If there is any resistance we have to subtract that dissipated energy(heat) from this net energy
part b:
The statement is not clear but what I make out of it is that amount of gasoline (in liter ) is required to get the same energy as part A
CV of gasoline=45MJ/kg
Total energy= mass *CV= density* volume * CV=805*V(in m3) * 45*106
805*(V(in liter)/1000 )* 45*106 = 1,872,000 J
V=0.0516 liters
part c
power from generator= 0.35kW=350J/s
time to charge= 1872000/350=5348.5s=1.485hours
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