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Question

session.masteringphysics.com Netflix ROKOtv I Ep Hours I Leddy Chegg Study direction of net f Copy of University Physics with Modern Physics Young/Freedman 14e KAssignment 3 Problem 24.53 5 of 11> Part A In the figure (Figure 1), Ci C5-8.3 F and C2-C3 4.4 AF. The applied potential is Vab 250 V C4 What is the equivalent capacitance of the network between points a and b? Express your answer using two significant figures. Submit Part B Figure 1 of Calculate the charge on capacitor C1 Express your answer using two significant figures. (a Request Answer Part C Calculate the potential diference across capacitor C Express your answer using two significant figures

Explanation / Answer

Remember:

For parallel combination

Ceq = C1 + C2 + C3 +...............

for series combination

1/Ceq = 1/C1 + 1/C2 + 1/C3 + ............

for 2 capacitors in series it will be

Ceq = C1*C2/(C1+C2)

Using this Information:

C3 and C4 are in series, & C3 = C4

C34 = 4.4/2 = 2.2 uF

C2 and C34 are in parallel, So

C234 = 2.2 + 4.4 = 6.6 uF

C1, C5 and C234 are in series, So

1/Ceq = 1/8.3 + 1/8.3 + 1/6.6

Ceq = (1/8.3 + 1/8.3 + 1/6.6)^-1

Ceq = 2.5 uF

Qeq = Ceq*V = 2.5*10^-6*250

Qeq = 6.3*10^-4 C

Now remember in capacitors parallel combination voltage distribution in each part will be same and in series combination charge distribution in each capacitor will be same.

Q1 = Q5 = Q234 = Qeq

Q1 = 6.3*10^-4 C

V1 = Q1/C1 = 6.3*10^-4/(8.3*10^-6) = 76 V

Q5 = 6.3*10^-4 C

V5 = Q5/C5 = 6.3*10^-4/(8.3*10^-6) = 76 V

Q234 = 6.3*10^-4 C

V234 = Q234/C234 = 6.3*10^-4/(6.6*10^-6) = 95 V

Since V2 and V34 are in parallel, So

V2 = V34 = V234

V2 = 95 V

Q2 = C2*V2 = 4.4*10^-6*95 = 4.2*10^-4 C

V34 = 95 V

Q34 = 2.2*10^-6*95 = 2.1*10^-4 C

Since Q3 and Q4 are in series, So

Q3 = Q4 = Q34

Q3 = 2.1*10^-4 C

V3 = Q3/C3 = 2.1*10^-4/(4.4*10^-6) = 48 V

Q4 = 2.1*10^-4 C

V4 = Q4/C4 = 2.1*10^-4/(4.4*10^-6) = 48 V

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