The first excited state of an atom of a gas is 4.35 eV above the ground state. W

Question

The first excited state of an atom of a gas is 4.35 eV above the ground state. What is the wavelength of radiation for resonance absorption? Give your answer in nm 286.9 nm 286.9 OK Correct! The energy of the radiation is equal to the energy gap between the ground state and first excited state. I attempt(s) made (maximum allowed for credit -5) [after that, multiply credit by 0.5 up to 10 attempts] If the gas is irradiated with monochromatic light of 231 nm wavelength, what is the wavelength of the Raman scattered light? Give your answer in nm m Enter Help

Explanation / Answer

Answer:

Given First ecited state of atom = 4.35eV

Wave Length = hc/L = 1240/4.35 = 285.057nm

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