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ID: 1730753 • Letter: T
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The Expert TA Human-ii x on/TakeTutorialAssignment-aspx Amessage from the Chiopractic OSH Arywhere. Sh Shopping?School?Puppies G Google l Help 7/31/2018 5:00:00 PM Homework 07 Begin Date: 7/24/2018 5:0000 PM-Due Date:7/31/2018 5.00.00 PM End Date (7%) Problem 13. Tree children are nding on the edge of a merry-goro d that is a disk of mass 98 kg radius 1.3 m at 18 rpm. The children have masses of 20 4 kg, 26 kg, and 34.6 kg. and is spun ng Randomized Variables M=98kg m 20.4 kg m 26 kg m-346 kg r= 1.3 m f 18 rpm D à If the child who has a mass of 26 kg moves to the center of the merry-go-round, what is the new magnitude of angular velocity in rpm? Grade Summ Potential cotan asi acoso atan0 acotan) sinh0 Submissions Atteragts ren (1% per ame detailed vies cosh tanho cotanho . Degrees Radians Sobenst Hint Hists: 0s deduction per hint Hints remaining Feedback:?" deduction per feedbackExplanation / Answer
Moment of merry go round=0.5*M*R^2=82.81 kgm^2
moment of childs when at distance r from center =mr^2
moment of inertia of person 1=34.476 kgm^2
person2=43.94 kgm^2
person3=58.474 kgm^2
let new angular velocity is w
conserving angular momentum
(82.81+58.474+34.476+43.94)*18=(82.81+34.476+58.474)*w
w=22.5 rpm
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