A mass less string is pulled with a force 79 N to the right.The string is wrappe

Question

A mass less string is pulled with a force 79 N to the right.The string is wrapped around a frictionless pully of non zeromoment of inertia and radius of .5 m and lifts a hanging block ofmass m=5kg. The tension between the pully and the block is 59N. A) Determin acceleration    a=2 m/s B) What is the angular acceleration of the pully? (no slipageon the pully) C) What is the net torque on the pully? D) What is the moment of inertia of the pully? A mass less string is pulled with a force 79 N to the right.The string is wrapped around a frictionless pully of non zeromoment of inertia and radius of .5 m and lifts a hanging block ofmass m=5kg. The tension between the pully and the block is 59N. A) Determin acceleration    a=2 m/s B) What is the angular acceleration of the pully? (no slipageon the pully) C) What is the net torque on the pully? D) What is the moment of inertia of the pully?

Explanation / Answer

so
2=alpha*5 alpha =2/5
The net torque is the sum of all the torques on thepulley. torque = FxR The cross product of force and theradius
so t= -mgblock*radius+ Fpulled*radius
torque = -59*R+79*R    theradiuses cancel tourqe= 20 N/m

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