hey guys, i have my physics two final tomorrow and i reallyneed to do good so i

Question

hey guys, i have my physics two final tomorrow and i reallyneed to do good so i can graduate next saturday so if i can getsome help i would really appreciate it!! the problem is : a proton moving horizontally enteruniform, verticat, 0.500T magnetic field and follows a circulararcc of radius 55.6cm. the speed of the proton as it entersthe magnetic field is? im sure i will have some more as i keep going through mytest hey guys, i have my physics two final tomorrow and i reallyneed to do good so i can graduate next saturday so if i can getsome help i would really appreciate it!! the problem is : a proton moving horizontally enteruniform, verticat, 0.500T magnetic field and follows a circulararcc of radius 55.6cm. the speed of the proton as it entersthe magnetic field is? im sure i will have some more as i keep going through mytest

Explanation / Answer

force from field is    F =qvB      circ motion   F =mv2 / r . So... .      q v B = m v2 /r .     v = q B r / m =   1.60 x 10-19 * 0.500 * 0.556 / 1.67 x10-27 = .          =    2.66 x107 m/s    

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