A heat engine performs the reversible cycle abca with9.0 moles of an ideal gas.

Question

A heat engine performs the reversible cycle abca with9.0 moles of an ideal gas. Path ca is an adiabaticprocess. The temperatures at points aand b are 300 K and 500 K, respectively. Thevolume at point c is 0.20 m^3. The adiabatic constant of thegas is 1.60. The work done by the gas in path ab, inkJ is? A heat engine performs the reversible cycle abca with9.0 moles of an ideal gas. Path ca is an adiabaticprocess. The temperatures at points aand b are 300 K and 500 K, respectively. Thevolume at point c is 0.20 m^3. The adiabatic constant of thegas is 1.60. The work done by the gas in path ab, inkJ is?

Explanation / Answer

The work done by the gas in path ab is W = P dV for ideal gas PV = nRT    PdV+VdP =nRdT at constant pressure PdV = nRdT    since dP =0 So, work done W =nRdT                              =(9 moles) ( 8.314 J / mol -K ) ( 500K - 300K )                             = 14965.2 J

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