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Theprimary coil of a transformer has 4,677 loops. The secondary coilhas 564,121

ID: 1728437 • Letter: T

Question

Theprimary coil of a transformer has 4,677 loops. The secondary coilhas 564,121 loops. The primary coil has a 51 A current and 18V.

a.) Is this a step-up or step-down transformer? How do you know?Choose one of the following.

1

It isa step-down transformer because all transformersare step-down transformers. It is a step-downtransformer because the primary current is greater than the primaryvoltage.     It is astep-up transformer because the primary current isgreater than the primary voltage. It is astep-down transformer because the secondary hasmore loops than the primary. It is a step-up transformerbecause the secondary has more loops than the primary. It is astep-up transformer because all transformers arestep-up transformers.



b.) Determine the power of the primary coil.
2 W
c.) Assuming no losses, determine the power of the secondarycoil.
3 W
d.) Calculate the voltage in the secondary coil.
4 V
e.) Calculate the current in the secondary coil.
5 A

Explanation / Answer

    a)     It is a step-up transformerbecause the secondary has more loops than the primary. ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~     b)     No. of loops primary coil, N1 = 4677     No. of loops in secondary coil, N2 = 564,121     Current on the primary coil, I1 = 51 A     Voltage of primary, V1 = 18 V     Power of primary coil, P1 = V1 I1                                            = 18 * 51                                            = 918 W ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~     c)     In case of no losses,     Power of secondary coil = Power of primarycoil                                          = 918 W ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~     d)        V2 / V1 = N2 / N1        V2 / 18 = 564121 / 4677        Voltage in the secondary coil, V2 =2171.1 V ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~     e)     I1 / I2 = N2 / N1     I2 = I1 * ( N1 / N2 )      Current in the secondary coil, I2 = 51 * (4677 / 564121 )                                                       = 0.42 A