Objects with masses of 130 kg and a430 kg are separated by 0.390 m. (a) Find the
ID: 1728393 • Letter: O
Question
Objects with masses of 130 kg and a430 kg are separated by 0.390 m. (a) Find the net gravitational force exerted bythese objects on a 39.0 kg object placedmidway between them.1 N
(b) At what position (other than infinitely remote ones) can the39.0 kg object be placed so as toexperience a net force of zero?
2 m from the 430 kgmass (a) Find the net gravitational force exerted bythese objects on a 39.0 kg object placedmidway between them.
1 N
(b) At what position (other than infinitely remote ones) can the39.0 kg object be placed so as toexperience a net force of zero?
2 m from the 430 kgmass
Explanation / Answer
masses m = 130 kg m'= 430 kg distance of separation r = 0.390 m (a). the net gravitational force exerted by these objects on a39.0 kg object placed midway between themis F = (GMm / x ^ 2 ) + ( GMm ' / x ^ 2 ) where x = distanc eof the mid point from one of themasses = r / 2= 0.195 m G =Gravitational constant = 6.67* 10 ^ -11 N m ^ 2 / kg ^ 2 M =mass kept at center = 39 kg So, F = [ GM /x^2 ] * ( m+ m' ) (b). If the force on 39 kg due to 130 kg is equal and oppositeto the force on 39 kg due to 430 kgthen net force is zero GMm ' / y ^ 2 = GMm /(r-y) ^ 2 m ' / m = ( [ y / ( r-y)] ^ 2 plug the values weget required distance y valueRelated Questions
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