A 4.0 kg block at rest on a tabletopis attached to a horizontal spring having co
ID: 1728291 • Letter: A
Question
A 4.0 kg block at rest on a tabletopis attached to a horizontal spring having constant 19.6 N/m as inFigure P13.12. The spring is initially unstretched. A constant 20 Nhorizontal force is applied to the object, causing the spring tostretch. (a) Determine the speed of the block after ithas moved 0.200 m from equilibrium ifthe surface between the block and tabletop is frictionless.(b) Answer part (a) if the coefficient of kinetic friction betweenblock and tabletop is 0.200.
m/s (a) Determine the speed of the block after ithas moved 0.200 m from equilibrium ifthe surface between the block and tabletop is frictionless.
(b) Answer part (a) if the coefficient of kinetic friction betweenblock and tabletop is 0.200.
m/s
Explanation / Answer
total work done = final kinetic energy . work of applied force - work done byfriction - work done by spring = (1/2) mv2 . 20 *0.200 - 0 - (1/2) *19.6 * 0.2002 = (1/2) *4.00 * v2 . v = 1.343 m/s . Now for part b, the only thing different is work byfriction: . 20 *0.200 - 0.200*4.00*9.80*0.200 - (1/2) *19.6 * 0.2002 = (1/2) *4.00 * v2 . v = 1.010 m/s . v = 1.343 m/s . Now for part b, the only thing different is work byfriction: . 20 *0.200 - 0.200*4.00*9.80*0.200 - (1/2) *19.6 * 0.2002 = (1/2) *4.00 * v2 . v = 1.010 m/sRelated Questions
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