1. two converging lenses are placed as in the figure. Find the position of the i

Question

1. two converging lenses are placed as in the figure. Find the position of the image formed by the first lens. a. 60cm, left of lens 1 b. 30cm, left c. 30 cm, right d. 60cm, right 2. The image formed by lens 1 is a. upright, magnified b. upright, diminished c. inverted, magnified d. inverted, diminished 3. Find the position of the final image relative to lens2. a. |d|>14cm, left b. |d|<14cm, left c. |d|>14cm, right d. |d|<14cm, right 4. The final image is a. upright, magnified b. upright, diminished c. inverted, magnified d. inverted, diminished a. upright, magnified b. upright, diminished c. inverted, magnified d. inverted, diminished

Explanation / Answer

.    Object distance (u) = 30.0 cm .    Focal length of firstlens (f1) = 20 cm . From Lens maker's formula we have : .    1 / f1 = 1 / u1 + 1/v1 .    or 1 / v1 = 1 / f1 - 1 / u1 = 1 / 20 - 1 /30 .    or v1 = 60 cm . Hence Image distance of the first lens is 60 cm right and Image formed is upright and magnified. . This image distance will be the object distance for secondlens . . Hence u2 = 20 - 60 = -40 cm .    Therefore Image distanceis : .    1 / v2 = 1 / f2 - 1 / u2    .       = 1 / 20 + 1/ 40 .    v2 = 13.333   ˜ 14 cm . Image relative to second lens is : < 14 cmright . Image is upright and magnified. . Hope this helps u!

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