In The figure above, the cube is 40 cm on each edge. Fourstraight-line segments,

Question

In The figure above, the cube is 40 cm on each edge. Fourstraight-line segments, ab, bc, cd, and da form a closed loop thatcarries a current I = 5 A. A uniform magnetic field B = 0.02 T isin the positive y-direction. What is the magnitude of the magneticforce on the wire segment da?

The magnitude of the force is F = IlBsinq, where q is the smallestangle between the directions of B and the current flow,

The angle between B and the current flow in the segment da is90o, sinq = 1.

So F = I*l*B. Here l is the length of the diagonal.

Explanation / Answer

a = 40 cm, I = 5 A. B = 0.02 T F = I*l*B. l = 2 a F = I*2 a*B = 0.057 N answer: C)

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