What is the binding energy of a 228/90 Th nucleus in MeV ifthe mass neutral Th a

Question

What is the binding energy of a 228/90 Th nucleus in MeV ifthe mass neutral Th atom is 228.028716? E = change in M x speed of sound squared. Change in M = M - M neutral M = Mp + Mn + Me Electron =       9.1094 x 10 to-31   or 0.00054858 u Proton   =      1.67262 x 10 to -27 or 1.07276 u Neutron =       1.67493 x10 to -27 or 1.008665 u This is from Applied Phyiscs Ninth Edition by Dale Ewen, NeillScuter, and P. Erik Gundersen The answer is given in the back of the book, but I cannot evenget close to it.They say it is 1750MeV What is the binding energy of a 228/90 Th nucleus in MeV ifthe mass neutral Th atom is 228.028716? E = change in M x speed of sound squared. Change in M = M - M neutral M = Mp + Mn + Me Electron =       9.1094 x 10 to-31   or 0.00054858 u Proton   =      1.67262 x 10 to -27 or 1.07276 u Neutron =       1.67493 x10 to -27 or 1.008665 u This is from Applied Phyiscs Ninth Edition by Dale Ewen, NeillScuter, and P. Erik Gundersen The answer is given in the back of the book, but I cannot evenget close to it.They say it is 1750MeV

Explanation / Answer

   for the given problem let us take that
   mp as mass of proton
   me as mass of electron
   mn as mass of nuetron
   M is the mass of nucleus
   Z is atomic number and
   A is the mass number
   then the mass defect will be
   m = [Z mp + (A - Z)mn] - M
   then the binding energy will be
   BE = m c2
   BE per nucleon will be = BE / A

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