If a force of magnitude 5N is applied to each end of a springcausing the spring

Question

If a force of magnitude 5N is applied to each end of a springcausing the spring to stretch 3.5 cm from it's relaxed length, howmuch work is done by the applied force in stretching the spring 3.5cm from it's relaxed length?
Is the solutions just work= Force*length? My bookis saying to half my answer as if it were "The triangular areaunder a forces on the spring versus the strength of the springgraph, which is the work done by the forces." That doesn'tseem accurate?
Is the solutions just work= Force*length? My bookis saying to half my answer as if it were "The triangular areaunder a forces on the spring versus the strength of the springgraph, which is the work done by the forces." That doesn'tseem accurate?

Explanation / Answer

F = 5 N, x = 3.5 cm force F = kx is not a constant, average force = kx/2 work = (kx/2)*x = kx2/2 = (F/x)*x2/2 = F*x/2= 8.75 N

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