A cardinal ( Richmondena cardinalis )of mass 4.10×10 2 kg and a baseball ofmass

Question

A cardinal (Richmondena cardinalis)of mass 4.10×102 kg and a baseball ofmass 0.146 kg have the same kinetic energy. What is the ratioof the cardinal's magnitude pc of momentum to themagnitude pb of the baseball's momentum? A. Pc / Pb A man weighing 660 N and a womanweighing 490 N have the same momentum. What is the ratio ofthe man's kinetic energy Km to that of the womanKw? B.Km / Kw A cardinal (Richmondena cardinalis)of mass 4.10×102 kg and a baseball ofmass 0.146 kg have the same kinetic energy. What is the ratioof the cardinal's magnitude pc of momentum to themagnitude pb of the baseball's momentum? A. Pc / Pb A man weighing 660 N and a womanweighing 490 N have the same momentum. What is the ratio ofthe man's kinetic energy Km to that of the womanKw? B.Km / Kw A man weighing 660 N and a womanweighing 490 N have the same momentum. What is the ratio ofthe man's kinetic energy Km to that of the womanKw? B.Km / Kw A man weighing 660 N and a womanweighing 490 N have the same momentum. What is the ratio ofthe man's kinetic energy Km to that of the womanKw? B.Km / Kw

Explanation / Answer

        Given A )     mass of the cardinal  mc = 4.10 x10-2           massof base ball     mb = 0.146 kg         the given conditionis                 kinetic energy of cardinal = kinetic energy of baseball                   (1/2)mcv2                     = (1/2 ) mb v2                             pc2/ 2 mc = pb2 /2mb                              pc2   / pb2   = mc /mb                                  pc / pb   = mc / mb                                                =   0.041/0.146                                                 = 0.5299 B) man weight     Wm = 660 N      woman weight  Ww   = 490 n              Given condition is man and women have same momentum                                pm   = pw                       Momentum, p is
                                  p= mv
                        Kinetic energy, KE is        KE=.5*mv2
                      The Kinetic energy can bewritten          KE=.5*p*v
                     Km/Kw = vm/vw (sincethey both have the same momentum)
                    findvm/vw    by    dividing the momentums    pm/pw =mmvm/(mwvw) = 1
                  you should also know that weight is equal to mass times gravityor
                                             W = mg
                              substituting this in gives

                                1 = Wm*vm/(Ww*vw)
                                             so
                                    vm/vw = Ww/Wm
                                            Km/Kw = Ww/Wm =490/660= 0.742                              pc2   / pb2   = mc /mb                                  pc / pb   = mc / mb                                                =   0.041/0.146                                                 = 0.5299 B) man weight     Wm = 660 N      woman weight  Ww   = 490 n              Given condition is man and women have same momentum                                pm   = pw                       Momentum, p is
                                  p= mv
                        Kinetic energy, KE is        KE=.5*mv2
                      The Kinetic energy can bewritten          KE=.5*p*v
                     Km/Kw = vm/vw (sincethey both have the same momentum)
                    findvm/vw    by    dividing the momentums    pm/pw =mmvm/(mwvw) = 1
                  you should also know that weight is equal to mass times gravityor
                                             W = mg
                              substituting this in gives

                                1 = Wm*vm/(Ww*vw)
                                             so
                                    vm/vw = Ww/Wm
                                            Km/Kw = Ww/Wm =490/660= 0.742                                                      

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