1 1 Work requires not only the force frompressure acting over an area, but also

Question

1 1 Work requires not only the force frompressure acting over an area, but also a displacement.
Work is done during such aprocess.
No work is done during such aprocess.
Heating a gas at constant volume doeswork.
Changing the pressure of a gas atconstant volume does work. 1 Work requires not only the force frompressure acting over an area, but also a displacement.
Work is done during such aprocess.
No work is done during such aprocess.
Heating a gas at constant volume doeswork.
Changing the pressure of a gas atconstant volume does work. 1

Explanation / Answer

    (a)     Initial volume, V1 = 1 m^3 Final volume, V2 = 2 m^3     Temperature, T = 850 K     No. of moles, n = 390 Universal gas constant, R = 8.3 J / mole / K     Work done, W = n R T ln ( V2 / V1 )                            = 390 * 8.3 * 850 * ln 2                            = 1.9 X 10 6 J     (b)     Work done, W = P V          (where P = pressure and V = change in volume )                            = P *0           ( V = 0 because volume is constant )                            = 0 J     Hence, HEATING A GAS AT CONSTANT VOLUME DOESNO WORK     Correct options:    Work requires not only the force frompressure acting over an area, but also a displacement     No work is done during such aprocess

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