Robert Galastyan, from Arenia, pulled two coupled railwaywagons a distance of 7

Question

Robert Galastyan, from Arenia, pulled two coupled railwaywagons a distance of 7 meters using his teeth. The total mass ofthe wagons was about 2.20*10^5 kg. Of course, his job was madeeasier by the fact that the wheels were free to roll. Suppose thewheels are blocked and the coefficient of static friction betweenthe rails and the sliding wheels is 0.220. what would be themagnitude of the minimum force needed to move the wagons from rest?Assume that the track is horizontal. *This is from a worksheet. I don't know what to do with thisinfo to solve the problem. The answer is: 4.75*10^5 Newtons.* Robert Galastyan, from Arenia, pulled two coupled railwaywagons a distance of 7 meters using his teeth. The total mass ofthe wagons was about 2.20*10^5 kg. Of course, his job was madeeasier by the fact that the wheels were free to roll. Suppose thewheels are blocked and the coefficient of static friction betweenthe rails and the sliding wheels is 0.220. what would be themagnitude of the minimum force needed to move the wagons from rest?Assume that the track is horizontal. *This is from a worksheet. I don't know what to do with thisinfo to solve the problem. The answer is: 4.75*10^5 Newtons.*

Explanation / Answer

Fy = N - mg Fy = 0 , since there is no acceleration along the ydirecion 0 = N - mg N = mg N = (2.20*10^5 kg) (9.8 m / s^2) N = 2.156 x 10 ^6 newtons
We know that the friction force is givenby k*N (2.156 * 10^6 N ) * .220 = 4.75 x 10 ^5 newtonsANSWER

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