the question reads: A 50kg disc with radius 0.8 m is spinning at 20 rads/s when

Question

1. A 50kg disc with radius 0.8 m is spinning at 20 rads/s when two20kg masses fall from above and stick to opposite edges of thedisk. By conservation of angular momentum, the angularvelocity of the system is reduced to   _______Rad/s

1. A 50kg disc with radius 0.8 m is spinning at 20 rads/s when two20kg masses fall from above and stick to opposite edges of thedisk. By conservation of angular momentum, the angularvelocity of the system is reduced to   _______Rad/s

Explanation / Answer

     Given that the mass of disk is M = 50kg           radius ofdisk is r = 0.8 m           initialangular velocity of the table is 1 = 20 rad/s    mass of person is m = 20kg ---------------------------------------------------------------------------      The angular moementum L = I*      Initial moment of inertia of the table isI1 = (1/2)Mr2                                                                   = 16 kg.m2    final moment of inertia of the table +parachutist is I2 = (1/2)Mr2 + mr2                                                                      = 16 kg.m2 +12.8 kg.m2                                                                                = 28.8kg.m2       since there is no external forceacting on the system angular momentum conserved                        initial angular momentum = final angular momentum                                      I1 * 1 = ( I2) *2                                                          2 = I1*1 / I2                                                                = ---------- rad/s

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