3. A wheel starts from rest and has an angular acceleration of4.0 rad / s / s. W

Question

3. A wheel starts from rest and has an angular acceleration of4.0 rad / s / s. What is its angular velocity after it has made 10revolutions?

16 rad /s
22 rad /s
32 rad /s
250 rad /s
500 rad /s
-------------------------------------------------- I used equation10.8 where the final angular velocity squared equals the initialangular velocity squared times 2 times the angular accelerationtimes (Final angle-Initial angle)
Where here theinitial angular velocity is 0 and the angular acceleration is 4rad/s/s and the Final angle i took 10 revolutions and multiplied by2 pi to get 62.83 radians. Would this be the right way ofsolving?

-------------------------------------------------- I used equation10.8 where the final angular velocity squared equals the initialangular velocity squared times 2 times the angular accelerationtimes (Final angle-Initial angle)
Where here theinitial angular velocity is 0 and the angular acceleration is 4rad/s/s and the Final angle i took 10 revolutions and multiplied by2 pi to get 62.83 radians. Would this be the right way ofsolving?

Explanation / Answer

         Given that theinitial angular velocity is 1 = 0 rad/s         angular acceleration is = 4.0 rad/s         angular displacement is = 10 rev = ( 10 rev) ( 2 rad / 1 rev ) = 62.8 rad ----------------------------------------------------------------------------------------      From the equation of motion    22 -12 = 2                                      2 = (2)   ( since 1 = 0)                                            = 22.41 rad/s

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